https://leetcode.cn/problems/add-two-numbers/description/

给你两个 非空 的链表,表示两个非负的整数。它们每位数字都是按照 逆序 的方式存储的,并且每个节点只能存储 一位 数字。

请你将两个数相加,并以相同形式返回一个表示和的链表。

你可以假设除了数字 0 之外,这两个数都不会以 0 开头。

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]:
        dummy = ListNode()
        remain = 0
        pointer = dummy

        while l1 or l2 or remain:
            v1 = l1.val if l1 else 0
            v2 = l2.val if l2 else 0
            pointer.next=ListNode((v1+v2+remain)%10)
            remain = (v1+v2+remain)//10
            if l1:
                l1 = l1.next
            if l2:
                l2 = l2.next
            if l1 or l2 or remain:
                pointer = pointer.next
        return dummy.next